### Math Riddle Answer.

I'm way overdue in posting the answer to the little math riddle I offered you guys a while back; I'm sorry, I've not been very much online.

There was a trick to it, of course. Mandating that

Henceforth, given

Furthermore,

Hence, of

Hence,

Additionally,

In conclusion,

Kudos to

I've unscreened the comments now.

The same woofiebutt also offers another problem, a lot more mathy:

Let

Calculate

And as for the rest, perhaps I'll post later on. We'll see.

There was a trick to it, of course. Mandating that

*p*be prime was not necessary. All it took was that*p*be odd. As is the case for all primes other than two!Henceforth, given

*p*any odd number:*(p-1)*and*(p+1)*are both even.Furthermore,

*(p-1)*and*(p+1)*are two consecutive even numbers, meaning that one of the two is a multiple of four.Hence, of

*(p-1)*and*(p+1)*, one is a multiple of*2*and the other is a multiple of*4*.Hence,

*(p-1).(p+1)*is a multiple of*8*.Additionally,

*(p-1)*,*p*and*(p+1)*being three consecutive numbers, one of them must be a multiple of*3*.In conclusion,

*(p-1).p.(p+1)*is a multiple of*8*3*=*24*.Kudos to

**grey_wolf_xvii**,**krdbuni**,**thenightwolf**,**kemonotsukai**and**janetraeness**for figuring it out! And honorable mention to**unciaa**and**timduru**for the witty answers. :) And thank you to the others for trying!I've unscreened the comments now.

**thenightwolf**also makes a good point that it was not that easy for the non-mathematician, because even though there is no advanced math concept involved, it does require a manner of mathematical thinking. I think he's right. So, uh, apologies for my lack of empathy in this.The same woofiebutt also offers another problem, a lot more mathy:

Let

*P*be a polynomial of degree*n*such that*P(i) = 1/i*for*i=1,...,n+1*.Calculate

*P(n+2)*.And as for the rest, perhaps I'll post later on. We'll see.